Optimal. Leaf size=210 \[ -\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{29 e^2 \sqrt{d^2-e^2 x^2}}{3 d^6 x}+\frac{2 e \sqrt{d^2-e^2 x^2}}{d^5 x^2}-\frac{\sqrt{d^2-e^2 x^2}}{3 d^4 x^3}+\frac{18 e^3 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{d^6} \]
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Rubi [A] time = 0.494123, antiderivative size = 210, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.259, Rules used = {852, 1805, 1807, 807, 266, 63, 208} \[ -\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{29 e^2 \sqrt{d^2-e^2 x^2}}{3 d^6 x}+\frac{2 e \sqrt{d^2-e^2 x^2}}{d^5 x^2}-\frac{\sqrt{d^2-e^2 x^2}}{3 d^4 x^3}+\frac{18 e^3 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{d^6} \]
Antiderivative was successfully verified.
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Rule 852
Rule 1805
Rule 1807
Rule 807
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{\sqrt{d^2-e^2 x^2}}{x^4 (d+e x)^4} \, dx &=\int \frac{(d-e x)^4}{x^4 \left (d^2-e^2 x^2\right )^{7/2}} \, dx\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{\int \frac{-5 d^4+20 d^3 e x-35 d^2 e^2 x^2+40 d e^3 x^3-32 e^4 x^4}{x^4 \left (d^2-e^2 x^2\right )^{5/2}} \, dx}{5 d^2}\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}+\frac{\int \frac{15 d^4-60 d^3 e x+120 d^2 e^2 x^2-180 d e^3 x^3+144 e^4 x^4}{x^4 \left (d^2-e^2 x^2\right )^{3/2}} \, dx}{15 d^4}\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{\int \frac{-15 d^4+60 d^3 e x-135 d^2 e^2 x^2+240 d e^3 x^3}{x^4 \sqrt{d^2-e^2 x^2}} \, dx}{15 d^6}\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{3 d^4 x^3}+\frac{\int \frac{-180 d^5 e+435 d^4 e^2 x-720 d^3 e^3 x^2}{x^3 \sqrt{d^2-e^2 x^2}} \, dx}{45 d^8}\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{3 d^4 x^3}+\frac{2 e \sqrt{d^2-e^2 x^2}}{d^5 x^2}-\frac{\int \frac{-870 d^6 e^2+1620 d^5 e^3 x}{x^2 \sqrt{d^2-e^2 x^2}} \, dx}{90 d^{10}}\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{3 d^4 x^3}+\frac{2 e \sqrt{d^2-e^2 x^2}}{d^5 x^2}-\frac{29 e^2 \sqrt{d^2-e^2 x^2}}{3 d^6 x}-\frac{\left (18 e^3\right ) \int \frac{1}{x \sqrt{d^2-e^2 x^2}} \, dx}{d^5}\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{3 d^4 x^3}+\frac{2 e \sqrt{d^2-e^2 x^2}}{d^5 x^2}-\frac{29 e^2 \sqrt{d^2-e^2 x^2}}{3 d^6 x}-\frac{\left (9 e^3\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{d^2-e^2 x}} \, dx,x,x^2\right )}{d^5}\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{3 d^4 x^3}+\frac{2 e \sqrt{d^2-e^2 x^2}}{d^5 x^2}-\frac{29 e^2 \sqrt{d^2-e^2 x^2}}{3 d^6 x}+\frac{(18 e) \operatorname{Subst}\left (\int \frac{1}{\frac{d^2}{e^2}-\frac{x^2}{e^2}} \, dx,x,\sqrt{d^2-e^2 x^2}\right )}{d^5}\\ &=-\frac{8 e^3 (d-e x)}{5 d^2 \left (d^2-e^2 x^2\right )^{5/2}}-\frac{4 e^3 (5 d-6 e x)}{5 d^4 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{e^3 (80 d-93 e x)}{5 d^6 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{3 d^4 x^3}+\frac{2 e \sqrt{d^2-e^2 x^2}}{d^5 x^2}-\frac{29 e^2 \sqrt{d^2-e^2 x^2}}{3 d^6 x}+\frac{18 e^3 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{d^6}\\ \end{align*}
Mathematica [A] time = 0.297746, size = 118, normalized size = 0.56 \[ -\frac{\frac{\sqrt{d^2-e^2 x^2} \left (70 d^3 e^2 x^2+674 d^2 e^3 x^3-15 d^4 e x+5 d^5+1002 d e^4 x^4+424 e^5 x^5\right )}{x^3 (d+e x)^3}-270 e^3 \log \left (\sqrt{d^2-e^2 x^2}+d\right )+270 e^3 \log (x)}{15 d^6} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.076, size = 412, normalized size = 2. \begin{align*} -18\,{\frac{{e}^{3}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}{{d}^{7}}}+18\,{\frac{{e}^{3}}{{d}^{5}\sqrt{{d}^{2}}}\ln \left ({\frac{2\,{d}^{2}+2\,\sqrt{{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}{x}} \right ) }-{\frac{1}{3\,{d}^{6}{x}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+10\,{\frac{{e}^{3}}{{d}^{7}}\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}+10\,{\frac{{e}^{4}}{{d}^{6}\sqrt{{e}^{2}}}\arctan \left ({\sqrt{{e}^{2}}x{\frac{1}{\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}}} \right ) }-{\frac{1}{5\,{d}^{5}e} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{3}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-4}}-{\frac{7}{5\,{d}^{6}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{3}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-3}}-10\,{\frac{e}{{d}^{7}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{3/2} \left ({\frac{d}{e}}+x \right ) ^{-2}}+2\,{\frac{e \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{3/2}}{{d}^{7}{x}^{2}}}-10\,{\frac{{e}^{2} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{3/2}}{{d}^{8}x}}-10\,{\frac{{e}^{4}x\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}{{d}^{8}}}-10\,{\frac{{e}^{4}}{{d}^{6}\sqrt{{e}^{2}}}\arctan \left ({\frac{\sqrt{{e}^{2}}x}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{-e^{2} x^{2} + d^{2}}}{{\left (e x + d\right )}^{4} x^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.92596, size = 448, normalized size = 2.13 \begin{align*} -\frac{324 \, e^{6} x^{6} + 972 \, d e^{5} x^{5} + 972 \, d^{2} e^{4} x^{4} + 324 \, d^{3} e^{3} x^{3} + 270 \,{\left (e^{6} x^{6} + 3 \, d e^{5} x^{5} + 3 \, d^{2} e^{4} x^{4} + d^{3} e^{3} x^{3}\right )} \log \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{x}\right ) +{\left (424 \, e^{5} x^{5} + 1002 \, d e^{4} x^{4} + 674 \, d^{2} e^{3} x^{3} + 70 \, d^{3} e^{2} x^{2} - 15 \, d^{4} e x + 5 \, d^{5}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{15 \,{\left (d^{6} e^{3} x^{6} + 3 \, d^{7} e^{2} x^{5} + 3 \, d^{8} e x^{4} + d^{9} x^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{- \left (- d + e x\right ) \left (d + e x\right )}}{x^{4} \left (d + e x\right )^{4}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.24081, size = 1, normalized size = 0. \begin{align*} +\infty \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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